Math 116 / Exam 2 (November 8, 2021 ) page 3
3. [14 points] Molly has recently become a sheep herder. She rotates her sheep through various
fields so that the sh eep have a varied diet and the fields have a chance to grow. Every Monday,
the sheep visit the same field. Before the sheep graze for the first time in this field, its grass
is 20 centimeters tall. Molly’s sheep are pi cky and only e at the top 40% of the length of grass
in this field every Monday. Over the course of the week, before the next Monday, the gr ass
grows 3 centimeters. Let G
i
represent the height in centimeters of the grass right before the
sheep graze on it for the ith time. Note that G
1
= 20.
a. [5 points] Find expression s for each of G
2
, G
3
, and G
4
. You do not need to evaluate your
expressions.
Solution:
G
2
= (0.6)G
1
+ 3
= (0.6)(20) + 3
G
3
= (0.6)G
2
+ 3
= (0.6)
2
(20) + (0.6)(3) + 3
G
4
= (0.6)G
3
+ 3
= (0.6)
3
(20) + (0.6)
2
(3) + (0.6)(3) + 3
b. [5 points] Find a general closed-form expression for G
n
, defined for n = 2, 3, 4 . . .
Solution:
G
n
= (0.6)
n−1
(20) +
n−2
X
i=0
3(0.6)
i
= (0.6)
n−1
(20) +
3(1 − (0.6)
n−1
)
1 − 0.6
c. [4 points] In order for the field to meet sheep grazing standards, the height of the grass
must be at least 5 cm when the sheep begin grazing. Molly thinks she will be able to stay
on her field forever. Help her determine whether she can stay by either showing that the
grass will eventually be less than 5 cm in height, or sh owing t hat the grass will be at least
5 cm each time before the sheep graze.
Solution:
lim
n→∞
G
n
=
3
1 − 0.6
= 7.5.
Also note that G
n
is a decreasing sequence. So, the grass is always taller than 5 cm.
when the sheep begin grazing.